About this parallel resistor calculator
In parallel, conductances add: 1/R = 1/R₁ + 1/R₂ + … For two resistors that is R₁R₂ ÷ (R₁ + R₂): 100 × 220 ÷ 320 = 68.75 Ω. The result is always smaller than the smallest resistor. In series you simply add them: 320 Ω.